In ∆abc and ∆def, ab = df and ∠a = ∠d. the two triangles will be congruent by sas axiom if:

In ∆abc and ∆def, ab = df and ∠a = ∠d. the two triangles will be congruent by sas axiom if:

Text Solution

BC=EFAC=DEAC=EFBC=DE

Answer : B

Solution : Given,in `Delta ABC " and " Delta DEF `,AB=DF and `angleA=angleD` <br> we know that,two triangle will be congruent by ASA rule,if two angles and the included side of one triangle are equal to the two angles and the included side of other triangle <br> `therefore " " AC=DE`

In triangles ABC and DEF, AB = FD and ∠A = ∠D. The two triangles will be congruent by SAS axiom if ______.

  • BC = EF

  • AC = DE

  • AC = EF

  • BC = DE

In triangles ABC and DEF, AB = FD and ∠A = ∠D. The two triangles will be congruent by SAS axiom if AC = DE.

Explanation:

Given, in ΔABC and ΔDEF, AB = DF and ∠A = ∠D

We know that, two triangles will be congruent by ASA rule, if two angles and the included side of one triangle are equal to the two angles and the included side of other triangle.

∴ AC = DE

Concept: Congruence of Triangles

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