Molarity = No of moles of soluteVolume of the solution in L =Mass of the given substance in g / Molar mass of HClVolume of the solution in L = 3.65 / 36.50.2 L = 0.5 M
 Text Solution Solution : Step 1: Calculate the moles of solute `(HCl):` <br> Number of moles of `HCl (n_(HCl)) = ("Mass Of HCl")/("Molar mass of HCl")` <br> `n_(HCl) = (3.65g)/(36.5g mol^(-1)) = 1.100 mol HCI` <br> Step 2: Apply the definition of molartiy using Eq (1.20) <br> `M = ("Molar of solute")/("Liners of soln".) = 0.050 "mol" HCl L^(_1) soln` <br> or `0.50 "mol" L^(-1)` <br> Alternatelty, in one setup, <br> `(? "mol" HCl)/(L soln) = (3.65 g HCl)/(2.00 "L soln") xx (1 "mol" HCl)/(36.5 g HCl) = 0.050 "mol" L^(-1)` |
3.65 g HCl was dissolved in 200 ml solution the molarity of solution is
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