As they travel through space, some light beams rotate. Such light beams have angular momentum. There are two particularly important ways in which a light beam can rotate: if every polarization vector rotates, the light has spin; if the phase structure rotates, the light has orbital angular momentum (OAM), which can be many times greater than the spin. Only in the past 20 years has it been realized that beams carrying OAM, which have an optical vortex along the axis, can be easily made in the laboratory. These light beams are able to spin microscopic objects, give rise to rotational frequency shifts, create new forms of imaging systems, and behave within nonlinear material to give new insights into quantum optics. ©2011 Optical Society of America Full Article | PDF Article More Like This
Optical communications using orbital angular momentum beams A. E. Willner, H. Huang, Y. Yan, Y. Ren, N. Ahmed, G. Xie, C. Bao, L. Li, Y. Cao, Z. Zhao, J. Wang, M. P. J. Lavery, M. Tur, S. Ramachandran, A. F. Molisch, N. Ashrafi, and S. Ashrafi
You do not have subscription access to this journal. Citation lists with outbound citation links are available to subscribers only. You may subscribe either as an Optica member, or as an authorized user of your institution. Contact your librarian or system administrator or Login to access Optica Member Subscription
You do not have subscription access to this journal. Cited by links are available to subscribers only. You may subscribe either as an Optica member, or as an authorized user of your institution. Contact your librarian or system administrator or Login to access Optica Member Subscription
You do not have subscription access to this journal. Figure files are available to subscribers only. You may subscribe either as an Optica member, or as an authorized user of your institution. Contact your librarian or system administrator or Login to access Optica Member Subscription
You do not have subscription access to this journal. Equations are available to subscribers only. You may subscribe either as an Optica member, or as an authorized user of your institution. Contact your librarian or system administrator or Login to access Optica Member Subscription Metrics
If you're seeing this message, it means we're having trouble loading external resources on our website. If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked.
Tardigrade - CET NEET JEE Exam App
© 2022 Tardigrade®. All rights reserved Text Solution `9.8 kg m^(2) s^(-1)`zero`52.7 kg m^(2) s^(-1)``37.9 kg m^(2) s^(-1)` Answer : A Solution : Total angular momentum about O is given as, <br> `L=L_(1)+L_(2)=m_(1)v_(1)r_(1)+m_(2)v_(2)r_(2)` <br> `=-6.5 xx2.2xx1.5+3.1xx3.6 xx2.8` <br> `=-21.45 + 31.248 = 9.8 "kgm"^(2) s^(-1)`. |