Let the two numbers be x and y respectively.Then,x + y = 8 ….(i)⇒ x = 8 - yAnd, `1/x + 1/y = 8/15` ⇒ `[ y + x ]/[xy] = 8/15` ⇒ `8/(xy) = 8/15` .....[ From(1) ]⇒ xy = 15⇒ ( 8 - y )y = 15 ⇒ 8y - y2 = 15 ⇒ y2 - 8y + 15 = 0 ⇒ y2 - 3y - 5y + 15 = 0⇒ y( y - 3 ) - 5( y - 3 ) = 0⇒ ( y - 3 )( y - 5 ) = 0⇒ y = 3 or y = 5⇒ x = 5 or x = 3 Thus, the two numbers are 3 and 5 respectively. Answer Verified> Solution Let the two natural numbers be x and y X+y=8 X=8-y ---(Equation-1) 1/x+1/y=8/15 ---(Equation -2) We get, 1/8-y+1/y=8/15 Y+8-y/-y2+8y=8/15 8/-y2+8y=8/15 120=-8y2+64y -8y2+64y=120 -8y2+64y-120=0 8y2-64y+120=0 y2-8y+15=0 y2-5y-3y+15=0 (sum=-8,Product=15) y(y-5)-3(y-5)=0 y-5=0 (or)y-3=0 y=5 (or) y=3 If y=5 then x=8-5 X=3 If y=3 then x=8-3 X=5 Therefore the two natural numbers are 3and 5 Suggest Corrections 0
Given Data: Sum of two natural number is 8. The sum of their reciprocals is 8/15. Concept Used: (a + b)2 = (a – b)2 + 4ab Calculation: Let the number be a and b. a + b = 8 …(i) 1/a + 1/b = 8/15 ⇒ (b + a)/ab = 8/15 ⇒ 8/ab = 8/15 ⇒ ab = 15 (a + b)2 = (a – b)2 + 4ab ⇒ 82 = (a – b)2 + 4 × 15 ⇒ 64 = (a – b)2 + 60 ⇒ (a – b)2 = 4 ⇒ a – b = 2 ….(ii) Adding (i) and (ii), 2a = 10 ⇒ a = 5 and b = 3 ∴ The two natural numbers are 5 and 3. Shortcut: Directly we can get the value from option 4, as a + b = 8 and ab = 15. India’s #1 Learning Platform Start Complete Exam Preparation
Video Lessons & PDF Notes Trusted by 2,78,24,673+ Students |