8. find two terms of the sequence t_{n} = 3n

The nth term is given by 3n+2, so for the first term, this is when n=1, so we substitute 1 as n and do a similar thing for 2nd and 3rd terms. 1st term (n=1): 3(1)+2= 3+2=5 2nd term (n=2): 3(2)+2=6+2=8 3rd term (n=3): 3(3)+2= 9+2=11 ... the 10th term of the sequence is when n=10 so we substitute n=10 into the nth term formula which gives: 3(10)+2=30+2=32

$8. find two terms of the sequence t_{n} = 3n - 2$

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The first term is when n= 1 3(1)+2 = 3+2 = 5 The second term is when n= 2 3(2)+2 = 6+2 = 8 The third term is when n=3 3(3)+2 = 11 The tenth term is when n=10 3(10)+2 = 30+2 = 32

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1st term: 3*1+2=5 2nd term: 3*2+2=8 3rd term: 3*3+2=11 10th term: 3*10+2=32

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n can take any value, in part A, let n=1,2,3. When n=1, 3(1)+2=5 n=2, 3(2)+2= 8 n=3, 3(3)+2= 11 For part B, the 10th term indicates n=10, hence 3(10)+2= 32

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To find out the first three terms of 3n + 2 substitute 1 ,2 and 3 into the equation. 3(1)+2=5 3(2)+2=8 3(3)+2=11 As you can see the sequence goes up in 3s 5 ,8, 11 To find out the 10th term you also substitute 10 into the equation so 3(10)+2=32 Hope this helped!

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N represents the number of term A) for the 1st three terms, just substitute n with 1,2 and 3 1st term: 3(1) + 2 = 5 2nd term: 8 3rd term: 11 B) 10th term: 3(10)+2= 32 You can check the answer by using the method: if n is the number of term, then 3n would represent multiples of 3. In this question, the answer will always be 2 more than any multiples of 3 (given n is a number)

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25-3n work out the first 3 sequences

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