When you reverse the digits in a certain two digit number you decrease its value by 36 find the number if the sum of its digits is 10?

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If we do so we decrease the first number by 18. So,

#10a+b-18=10b+a#

Solving equation (1) and (2)
#a+b=10#... (1)
#a-b=2#... (2)

In equation (2).
#a-b=2#
# or, a=2+b#

Substitute in equation (1).
#a+b=10#
# or, 2+b+b=10#
# or, 2+2b=10#
# or, 2 (1+b)=10#
# or, 1+b=(10/2)#
# or, 1+b=5#
#:.b=5-1=4#

Re substitute in equation (1)
#a+b=10#
# or, a+4=10#
#:.a=10-4=6#

The numbers are #4# and #6#

Hi sum of its digits is 10 Let x and (10-x)represent the unit and tens digits of this certain two-digit number Question states*** Note: [10*(10-x)+ x] the original number 10*x + (10-x) = [10*(10-x)+ x] - 36 Solving for x 9x + 10 = 100 - 9x - 36 18x = 54 x = 3, the units digit, 7 the ten digit, the Number is 73 CHECKING our Answer***

37 = 73 - 36