Is 60% of first order reaction was completed in 60 minutes 50% of the same reaction would be completed in approximately?

The bromination of acetone that occurs in acid solution is represented by this equation.

CH3COCH3(aq) + Br2(aq) → CH3COCH2Br(aq) + Br-(aq)

These kinetic data were obtained for given reaction concentrations.

Initial concentrations, M

CH3COCH3 Br2 H+

0.30 0.05 0.05

0.30 0.10 0.05

0.30 0.10 0.10

0.40 0.05 0.20

Initial rate, disappearance of Br2, Ms-1

5.7X10-5

1.2X10-4

3.1X10-4

Based on these data, the rate equation is

1. Rate = k [CH3COCH3] [H+]

2. Rate = k [CH=COCH3][Br2]

3. Rate = k [CH3COCH3][Br2][H+]2

4. Rate = k [CH3COCH3][Br2][H+]

Subtopic: Definition, Rate Constant, Rate Law |

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

To view explanation, please take trial in the course below.

NEET 2023 - Target Batch - Aryan Raj Singh

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A reaction is second order with respect to a reactant. How is the rate of rection affected if the concentration of the reactant is
(i) Doubled
(ii) Reduced to 1/2?

Let the reaction A → B is a 2nd order reaction w.r.t A and conc. of A is ‘a’ mol/L, then rate of reaction can be written as:

dxdt=k[A]2 =ka2

(i) When conc. [A] is doubled

i.e., [A’] = 2a mol/L
Then new rate of reaction

d'(x)dt=k[2a]2 = 4ka2 = 4dxdt

Thus rate of reaction will become four times where concentration is doubled.

(ii) Similarly, when conc. of A is reduced to 12 i.e., [A] is a/2 then new rate of reaction,

d'(x)dt = ka22 = 14ka2 = 14dxdt

The rate of reaction will become one-fourth of the initial rate of reaction.

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