What was the difference between the number of B type tyres manufactured in 1994 and 1995

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Common Solution for the questions:

From the given information, we can make the following table:

Answer 1: (b)

To find the maximum difference let us take the minimum values from September and the maximum values from October.

From September = 960+360 = 1320.

From October = 3750 +3000 = 6750.

The difference = 6750-1320 = 5430.

The correct option is (b)

Answer 2: (b)

There is only one absolute decrease i.e. for E.

The correct option is (b)

Answer 3: (d)

Sale of F type tyres in October = 1950.

In September

Sale of A and C = 360 + 2640 = 3000

Sale of C and E= 2640 + 2040 = 4680

Sale of B and D= 1560 + 3000 = 4560

Sale of A and B=360 + 1560 = 1920

The correct option is (d)

Answer 4: (b)

For E, there is a decrease in sales and for D, the sales for the two years are equal.

The total sale of all tyres except D and E in September = 12000 – 3000 – 2040 = 6960

The total sale of all tyres except D and E in October = 15000 – 3000 – 1500 = 10500

The required difference = 10500 – 6960 = 3540.

The correct option is (b)

Answer 5: (d)

Number of tyres of type D and E sold in September = 3000 + 2040 = 5040

Number of tyres of type D and E sold in October = 3000 + 1500 = 4500

Hence the required percentage = {(5040/4500)} x 100 = 112%

The only correct answer possible is (d)

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136. Study the following graph carefully and answer the questions given below:

Production of three types of tyres by a company over the year (in lakh)

Correct Answer
Explanation

Required difference = Number of B type tyres in 1994 - Number of B type tyres in 1995
Required difference = ( 27.5 ? 22.5 ) Million = 5 Million = 5000000.

1.
The total number of candidates passed from Rural in 1993 and Semi-urban in 1990 was exactly equal to the total number of candidates passed from State capital in which of the following years?
Options
A. 1990
B. 1993
C. 1994
D. 1992

Explanation:

The total number of candidates passed = Candidates passed from Rural in 1993 + Candidates passed from Semi-urban in 1990The total number of candidates passed = 1798 + 2513 = 4311.

From the given table graph check the number of passed candidate from state capital is 4311 which is 1994.

2.
In 1993 percentage of candidates passed to appeared was approximately 35 from which location?
Options
A. Rural
B. Rural and Metropolises
C. Semi-urban and Metropolises
D. Rural and Semi-urban

Explanation:

We do not need to calculate the values for each year. Follow as:For Rural area : 35% of 5032 ? 35 � 50 = 1750 ? 1798 For Semi-urban area : 35% of 9500 ? 35 � 95 ? 3300 Which cannot be approximated to 3500. For State capitals : 35 � 85 = 3000

For Metropolises : 35 � 110 = 3850

4.
In which of the following years was the percentage passed to appeared candidates from semi-urban area the least?
Options
A. 1991
B. 1993
C. 1990
D. 1992

Explanation:

Our intelligent observation says that the required year cannot be 1993, 1994, 1995. Why? Because see the following conclusions: % passed to appear = Passed / Appeared x 100 % of passed to appear is least when Passed / Appeared is the least or, Appeared / Passed is the most. Now, we do the further calculations mentally. See the following conclusions: For 1990: 7894 / 2513 ? Quotient = 3 and Remainder ? 300For 1991: 8562 / 2933 ? Q = 3 and R ? 400For 1992: 8139 / 2468 ? Q = 3 and R ? 800Similarly, for 1993; 1994, 1995, Q is 2.

So, 1992 gives the highest value.