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Southern Illinois University Carbondale
Joel B. Algebra 7 months, 3 weeks ago
The sum of three numbers is $40 .$ One number is five more than a second number. It is also twice the third. Find the numbers. Joana P. 1 Expert Answer We can start by letting x represent the first number. Then the second number can be represented by 2 x + 5 because twice x means multiply by 2 and 5 more than means add 5 Since the sum of the two numbers is 80, we can write the following equation and solve it to find the missing numbers: first number plus second number = 80 Then: x + 2x + 5 = 80 Now combine like terms and use inverse operations to determine the value of x (or the first number): x + 2x + 5 = 80 3x + 5 = 80 3x + 5 - 5 = 80 - 5 3x =75 3x/3 = 75/3 x = 25 So the first number is 25 The second will be 2x + 5 or 2 *25 + 5= 50 + 5 or 55 The second number is 55. Their sum is indeed 80 (i.e.25 + 55 = 80)
You can put this solution on YOUR website! Hi there, The second of two numbers is 5 more than twice the first. The sum of the numbers is 44. Make first number = x Second number = 2x + 5 Sum = x + (2x + 5) 44 = x + 2x + 5 39 = 3x 3x = 39 x = 13. First number = 13 Second number = 31 Hope this helps :-) |