Two masses m1 and m2 are connected to the ends of massless string

Text Solution

Answer : 2

Solution : If `veca` is the acceleration of`m_1` then `-veca` is the acceleration of `m_2`. <br> We know that `(m_1 + m_2) vecA cm. m_1veca_1 + m_2 veca_2` <br> or `(m_1 + m_2) vecA cm = m_1 veca - m_2veca " or "vecacm. = (m_1 - m_2)/(m_1 + m_2)veca` <br> But, `veca = (m -1 - m_2)/(m_1 + m_2) vecg` [connected - body problem] `:. " " vecAcm . = ((m_1 - m_2)^2)/((m_1 + m_2)^2) vecg`.