Open in App Suggest Corrections 0 Q.  From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain Solve the following pair of linear equations by the substitution and cross-multiplication methods: From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain (i) For which values of a and b will the following pair of linear equations have an infinite number of solutions? (ii) For which value of k will the following pair of linear equations have no solution? Which of the following pairs of linear equations has unique solution, no solution or infinitely many solutions? In case there is a unique solution, find it by using cross multiplication method. Q. From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain Solve the following pair of linear equations by the substitution and cross-multiplication methods: From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain From equation (ii), we obtain Substituting this value in equation (i), we obtain Substituting this value in equation (ii), we obtain Hence, Again, by cross-multiplication method, we obtain (i) For which values of a and b will the following pair of linear equations have an infinite number of solutions? (ii) For which value of k will the following pair of linear equations have no solution? Which of the following pairs of linear equations has unique solution, no solution or infinitely many solutions? In case there is a unique solution, find it by using cross multiplication method. |
Solve the following pair of linear equations by the substitution method and cross multiplication
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