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If A and B are two events such that <br> p(A) = 1/4, P(B) = 1/2and<br> = 1/8, find P (not A and not B). 1) 5/12 2) 3/8 3) 5/8 4) ½ Solution: Option (1) 5/12 Given that, P(AUB) = ¾, P(A∩B) = ¼, P(A’) = ⅔ P(A) = 1-P(A’) P(A) = 1- (⅔) = ⅓ Hence, P(B) = ⅔ P(A’∩B) = P(B) – P(A∩B) We know that, P(AUB) = P(A)+P(B) – P(A∩B) P(B) – P(A∩B) = P(AUB) – P(A) P(A’∩B) = (¾) – (⅓) P(A’∩B) = (9-4)/12 P(A’∩B) = 5/12.
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