How many two digit numbers can be formed from the digits 1,2 3 and 4 if repetitions are allowed?

Permutation and Combination #31

How many 2 digit numbers can be formed from the numbers 1 2 3 4 and 5 if repetitions are allowed?

Total Number of Numbers which can be formed by numbers 1,2,3,4,5 (without repeating digitsi) = 5*4*3*2*! = 5! = 120.

How many four digit numbers are possible from the digits 0 1 2 3 4 and 5 if I repetitions are allowed?

That exhausts the possibilities, so there are 120+300=420 even four digit numbers that can be formed using the digits 0,1,2,3,4,5,6.

How many even numbers can be formed from the digits 1 2 3 4?

Further, to ensure that the number is even we ensure that in the unit’s place, the digits can only be 2 or 4. Hence, there are 48 four digit even numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated.

How many 4 digit numbers can be formed from the digits 12345 which are divisible by 3?

Hence the units place can be filled in ‘2’ ways. Therefore, the number of 4 digited numbers divisible by 3. =63×2=216×2=432.

How many 6 digit even numbers can be formed from the digits 1 2 3 4 5 SO 7 the digits should not repeat and second last digit is even?

So, total number of numbers that can be formed with the digits {1, 2, 3, 4, 5, 6, 7} with no digits repeated and terminal digits as even will be 3×5×4×3×2×2 = 720. So, total possible numbers will be 720. Hence, the correct option will be D.

How many 4-digit even numbers can be formed using the digits 0 1 2 3 4 if all digits must be distinct?

How many 4-digit even numbers can be formed?

Hence, there are 48 four digit even numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated.