Find a cubic polynomial with the sum, sum of the product of its zeroes taken two at a time, and product of its zeros as 3, −1 and −3 respectively. Any cubic polynomial is of the form ax3 + bx2 + cx + d = x3 − sum of zeroes (x2)[product of zeroes] + sum of the products of its zeroes × - product of zeroes = 𝑥3 − 2𝑥2 + (3 − 𝑥) + 3 = k [𝑥3 − 3𝑥2 − 𝑥 − 3] k is any non-zero real numbers Concept: Relationship Between Zeroes and Coefficients of a Polynomial Is there an error in this question or solution?
Solution: We know that the general form of a cubic polynomial is ax3 + bx2 + cx + d and the zeroes are α, β, and γ. Let's look at the relation between sum, and product of its zeroes and coefficients of the polynomial.
Let the polynomial be ax3 + bx2 + cx + d and the zeroes are α, β, γ We know that, α + β + γ = 2/1 = - b / a αβ + βγ + γα = - 7/1 = c / a α.β.γ = - 14/1 = - d / a Thus, by comparing the coefficients we get, a = 1, then b = - 2, c = - 7 and d = 14 Now, substitute the values of a, b, c, and d in the cubic polynomial ax3 + bx2 + cx + d. Hence the polynomial is x3 - 2x2 - 7x + 14. ☛ Check: NCERT Solutions Class 10 Maths Chapter 2 Video Solution: Find a cubic polynomial with the sum, sum of the product of its zeroes taken two at a time, and the product of its zeroes as 2, - 7, - 14 respectivelyNCERT Solutions Class 10 Maths Chapter 2 Exercise 2.4 Question 2 Summary: A cubic polynomial with the sum, sum of the product of its zeroes taken two at a time, and the product of its zeroes as 2, - 7, - 14 respectively is x3 - 2x2 - 7x + 14. ☛ Related Questions:
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