Give the equation of two lines passing through 5,13 how many more lines are there, and why

Uh-Oh! That’s all you get for now.

We would love to personalise your learning journey. Sign Up to explore more.

Sign Up or Login

Skip for now

Uh-Oh! That’s all you get for now.

We would love to personalise your learning journey. Sign Up to explore more.

Sign Up or Login

Skip for now

Solution:

Given: Point (2, 14) at which lines passing through.

We can think of framing equations that could satisfy the given point (2, 14) on the line.

It can be observed that point (2, 14) satisfies the equation 7x - y = 0 and x - y + 12 = 0.

Therefore, 7x - y = 0 and x - y + 12 = 0 are two lines passing through point (2, 14).

Since we know infinite lines can pass through a single point, therefore there are infinite more lines passing through the given point

☛ Check: NCERT Solutions Class 9 Maths Chapter 4

Video Solution:

Give the equations of two lines passing through (2, 14). How many more such lines are there, and why?

NCERT Solutions Class 9 Maths Chapter 4 Exercise 4.3 Question 2

Summary:

The equations of two lines passing through (2, 14) are 7x − y = 0 and x − y + 12 = 0, there are infinite lines passing through the given point (2, 14).

☛ Related Questions:

Math worksheets and
visual curriculum

Text Solution

`" Infinite line"``" one line"``" Three lines"``" Four lines"`

Solution : Let the equation of straight line be <br> ax + by =c <br> It passes through (-5,13) <br> `therefore` , a(-5)+b(13)=c <br> `rArr` , -5a+13b=c <br> Now wse can take any arbitrary values of a and b to get c: <br> Let , a==0 and b =1 `rArr` c=13 <br> Putting these values of a,b and c in (1) we get <br> 0.cx+1.y=13 `rArr` y=13 <br> Let , a=4,b=2 `rArr` c=6 <br> putting these values of a,b and c in eq (1) we get <br> 4x+2y =6 `rArr` 2x+y=13 <br> In the same manner we can get so many equations <br> Hence, there may be <b> infinitely many lines </b> (equations) passing through (-5,13).