Using the digits 1, 2 and 3 how many two digits numbers can be formed if repetition is not allowed

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    As the title said, I have an assignment where we are asked: How many 2-digit numbers can be formed from even-numbered digits if the repetition of the digit is not allowed?

    I've tried answering it myself but I am not sure if it's correct. What I did was multiply 4 by 3, since there are 4 even-numbered digits (2, 4, 6, 8). And since repetition is not allowed, for the ones digit, I did 4 since nothing has been used yet and for the tens digit I only used 3 since one digit has been used before. Please correct me if I'm wrong.

    Sorry if my explanation is bad, I have a hard time trying to explain things and this is my first time posting. Many thanks!

    Edit: Okay, just a quick update. I asked my teacher and apparently, both 12 and 16 are considered answers. Case closed! :)

    1.Using the digits , and , how many two-digit numbers can be formed if repetition is not allowed? List down all the possible numbers below. 2.Three players were numbered as , and . How many teams of two players can be formed? List down all possible teams of two players below.

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