How to find second max value in list python without inbuilt function

Last update on May 28 2022 13:14:30 (UTC/GMT +8 hours)

Write a Python program to find the second largest number in a list.

Table of Contents Show

Visualize Python code execution:
Find Second Largest Number in List without using Function
Find Second Largest Number in List of Given Size
Find Second Largest Number in List using max()

Example - 1 :

Example - 2 :

Example - 3 :

Example - 4 :

Sample Solution:-

Python Code:

def second_largest(numbers): if (len(numbers)<2): return if ((len(numbers)==2) and (numbers[0] == numbers[1]) ): return dup_items = set() uniq_items = [] for x in numbers: if x not in dup_items: uniq_items.append(x) dup_items.add(x) uniq_items.sort() return uniq_items[-2] print(second_largest([1,2,3,4,4])) print(second_largest([1, 1, 1, 0, 0, 0, 2, -2, -2])) print(second_largest([2,2])) print(second_largest([1]))

Sample Output:

3 1 None None

Flowchart:

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This article is created to cover some programs in Python, that find and prints second largest number or element in a given list. Here are the list of programs covered in this article:

Find Second Largest Number in a List of 10 elements using for Loop
Find Second Largest Number in a List of N elements using for Loop
Find Second Largest Number in a List of given Size using max() Method

Find Second Largest Number in List without using Function

The question is, write a Python program that find second largest element in a list using for loop. Here is its answer:

nums = [] print("Enter 10 Elements (Numbers) for List: ") for i in range(10): nums.append(int(input())) large = nums[0] for i in range(10): if large<nums[i]: large = nums[i] secondLarge = nums[0] for i in range(10): if secondLarge<nums[i]: if nums[i]!=large: secondLarge=nums[i] print("\nSecond Largest Number is: ") print(secondLarge)

Here is its sample run:

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